TeX джерело:

\begin{array}{l}y{'_x} = y{'_u} \cdot u{'_x} = ({u^5})' \cdot (3{x^3} - 1)' = 5{u^4} \cdot 9{x^2} = 5{(3{x^3} - 1)^4} \cdot 9{x^2} = \\ = 45{x^2}{(3{x^3} - 1)^4}.\end{array}