TeX джерело:
\int\limits_1^2 {{{(x + 2)}^2}dx} = \frac{{{{(x + 2)}^3}}}{3}|_1^2 = \frac{{{{(2 + 2)}^3}}}{3} - \frac{{{{(1 + 2)}^3}}}{3} = \frac{{64 - 27}}{3} = \frac{{37}}{3} = 12\frac{1}{3}