TeX джерело:

{T_{m + 1}} = C_{16}^m{(\sqrt[3]{x})^{16 - m}} \cdot {(\frac{1}{x})^m} = C_{16}^m{x^{\frac{{16 - m}}{3}}}{x^{ - m}} = C_{16}^m{x^{\frac{{16 - 4m}}{3}}}